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Maths / Triangles / Angle Sum Property of a Triangle
QUESTION
 

The::angle::of ::a::triangle::are(x-40)^0,(x-20)^0andleft ( frac{1}{2}x-10 right ).find the value of angles

OPTIONS
A. 

120, 20,40

B. 

100, 50,30

C. 

90, 30,60

D. 

60, 80, 40

Right Option : D
EXPLANATION
Explain TypeExplanation Content
Text

large The:;sum ;angle::of ::a::triangle::= 180^0

large (x-40)^0 + (x-20)^0 + left ( frac{1}{2}x-10 right ) = 180^0

large x-40^0 + x-20^0 + frac{x}{2}-10^0 = 180^0

large 2x + frac{x}{2}-70^0 = 180^0

large frac{4x+x}{2} = 70^0 + 180^0

large frac{5x}{2} = 250^0

large 5x = 500^0

large x = 100^0

So; the::angle::of ::a::triangle::are(100-40)^0,(100-20)^0andleft ( frac{1}{2}100-10 right )

large 60^0, 80^0 andleft ( 50^0 -10^0 )

large 60^0, 80^0 and : 40^0

 

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